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removed bad proof for 3.
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S. Carnahan
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  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).

  2. You can do a sort of reflected version of the above, using increasing functions that jump at rationals and have rational slope elsewhere. Start with f(0)(x) = x, enumerate the rationals as r(i) with i ranging over positive integers. For each i, let f(i) be given by adding[removed due to f(i-1)being a function that is supported in the interval of radius 2^(-i) around r(i), continuous with slope -2^(-i) in this interval away from r(i), and setting f(i)(r_i) to be some irrational between the left and right limits of the jumpflawed argument (the right limit at r(i) is greater than the left limit by 2^(-2i+1)). As long as the rationals r(i) are chosen in a reasonably intelligent way, any real number is covered by at most finitely many of these intervals, so the function is both increasing and irrational-valued. Scott]

  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).

  2. You can do a sort of reflected version of the above, using increasing functions that jump at rationals and have rational slope elsewhere. Start with f(0)(x) = x, enumerate the rationals as r(i) with i ranging over positive integers. For each i, let f(i) be given by adding to f(i-1) a function that is supported in the interval of radius 2^(-i) around r(i), continuous with slope -2^(-i) in this interval away from r(i), and setting f(i)(r_i) to be some irrational between the left and right limits of the jump (the right limit at r(i) is greater than the left limit by 2^(-2i+1)). As long as the rationals r(i) are chosen in a reasonably intelligent way, any real number is covered by at most finitely many of these intervals, so the function is both increasing and irrational-valued.

  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).

  2. [removed due to being a flawed argument - Scott]

revise sentence for clarity
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S. Carnahan
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  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).

    Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).

  2. You can do a sort of reflected version of the above, using increasing functions that jump at rationals and have rational slope elsewhere. Start with f(0)(x) = x, enumerate the rationals as r(i) with i ranging over positive integers. For each i, let f(i) be given by adding to f(i-1) a function that is supported in the interval of radius 2^(-i) around r(i), continuous with slope -2^(-i) in this interval away from r(i), and setting f(i)(r_i) to be some irrational between the left and right limits of the jump (the right limit at r(i) is greater than the left limit by 2^(-2i+1)). As long as the rationals r(i) are chosen in a reasonably intelligent way, any real number is covered by at most finitely many of these intervals, so the function is both increasing and irrational-valued.

  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).
  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).

  2. You can do a sort of reflected version of the above, using increasing functions that jump at rationals and have rational slope elsewhere. Start with f(0)(x) = x, enumerate the rationals as r(i) with i ranging over positive integers. For each i, let f(i) be given by adding to f(i-1) a function that is supported in the interval of radius 2^(-i) around r(i), continuous with slope -2^(-i) in this interval away from r(i), and setting f(i)(r_i) to be some irrational between the left and right limits of the jump (the right limit at r(i) is greater than the left limit by 2^(-2i+1)). As long as the rationals r(i) are chosen in a reasonably intelligent way, any real number is covered by at most finitely many of these intervals, so the function is both increasing and irrational-valued.

added 11 characters in body
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S. Carnahan
  • 45.7k
  • 6
  • 114
  • 220
  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).
  1. Take any nondecreasing function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).
  1. Take any nondecreasing continuous function from the reals to the reals that is constant in neighborhoods of rationals, and restrict it to irrationals. This can be constructed as a uniform limit by starting with f(0)(x) = x, enumerating the rationals as r(i) and for each i, setting f(i+1)(x) to be a sum of f(i)(x) and some piecewise linear function supported in a neighborhood of radius 2^(-i) around r(i).
Source Link
S. Carnahan
  • 45.7k
  • 6
  • 114
  • 220
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