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Timeline for quasi-affine-ness [closed]

Current License: CC BY-SA 3.0

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Feb 15, 2018 at 18:58 history closed R. van Dobben de Bruyn
Stefan Kohl
abx
Jan-Christoph Schlage-Puchta
Pace Nielsen
Needs details or clarity
Feb 15, 2018 at 17:30 answer added Laurent Moret-Bailly timeline score: 5
Feb 15, 2018 at 15:27 comment added Jason Starr @LaurentMoret-Bailly You are correct. I was using the unipotent radical of a Borel subgroup.
Feb 15, 2018 at 14:02 answer added PiJay timeline score: 2
Feb 15, 2018 at 14:00 comment added Laurent Moret-Bailly I thought $R_u(G)$ was the unipotent radical of $G$. For $G=\mathrm{SL}_2$ it is trivial.
Feb 15, 2018 at 12:58 history edited user111251 CC BY-SA 3.0
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Feb 15, 2018 at 10:29 comment added Jason Starr For $G$ equal to $\textbf{SL}_2$, and for $H$ equal to $R_u(G)$, the quotient $G/H$ equals $\mathbb{A}^2\setminus\{(0,0)\}$. This is not affine. Did you intend to ask whether $G/H$ is quasi-affine?
Feb 14, 2018 at 22:53 review Close votes
Feb 15, 2018 at 18:58
Feb 14, 2018 at 19:26 history edited user111251 CC BY-SA 3.0
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Feb 14, 2018 at 18:53 history edited user111251 CC BY-SA 3.0
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Feb 14, 2018 at 18:53 comment added Jason Starr What is your definition of an $\mathbb{A}^n$-fibration? For a separated, finitely presented morphism, the property of being affine can be checked after flat, surjective base change. This can be proved using Serre's criterion for affineness, among other methods,
Feb 14, 2018 at 18:48 history edited user111251 CC BY-SA 3.0
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Feb 14, 2018 at 18:32 history asked user111251 CC BY-SA 3.0