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Feb 16, 2018 at 9:01 vote accept Tommi
Feb 14, 2018 at 18:47 answer added Nate Eldredge timeline score: 6
Feb 14, 2018 at 16:53 comment added Nate Eldredge Stone-Weierstrass says that if $f$ is continuous and injective, then $P_f$ is uniformly dense in $C(I)$, which implies it is dense in $L^2$. More generally, I think a necessary and sufficient condition would be that the $\sigma$-algebra $\sigma(f) = \sigma(f^{-1}(B) : B \in \mathcal{B}_{\mathbb{R}})$ contains the Borel $\sigma$-algebra of $I$ in its completion. I think we can prove this with the Dynkin multiplicative system lemma. I will try to flesh it out later if I get a chance.
Feb 14, 2018 at 14:21 history edited Tommi CC BY-SA 3.0
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Feb 14, 2018 at 13:55 comment added Jochen Wengenroth Perhaps this question mathoverflow.net/questions/96006/… has some relevance?
Feb 14, 2018 at 13:47 history edited Tommi CC BY-SA 3.0
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Feb 14, 2018 at 13:38 history asked Tommi CC BY-SA 3.0