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Nov 13, 2018 at 20:00 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Oct 14, 2018 at 19:40 answer added Federico Poloni timeline score: 1
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Aug 15, 2018 at 17:23 history edited David Handelman CC BY-SA 4.0
non is NOT a word (in English)
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Feb 16, 2018 at 13:43 history edited Abdu Magdy CC BY-SA 3.0
corrected some typos.
Feb 16, 2018 at 13:24 history edited Abdu Magdy CC BY-SA 3.0
corrected some typos.
Feb 16, 2018 at 12:59 comment added Abdu Magdy Dear @Peter Heinig, Thank you so much :)
Feb 16, 2018 at 9:08 comment added Peter Heinig Dear @ Abdu Magdy: I added the theorem that the statement you are asking about is a corollary of. Speaking to the content to your question: while I did not look long into Gantmacher's book, as far as I can see you have a point, in that while Theorem 3 ensures that $D_k D_{k-1}$ is nonzero, there does not seem to be any condition ensuring that it is $>0$.
Feb 16, 2018 at 9:06 history edited Peter Heinig CC BY-SA 3.0
Added the full reference to the book the OP is asking about. Added the theorem that the statement the OP is asking about is a corollary of.
Feb 14, 2018 at 18:39 vote accept Abdu Magdy
Feb 14, 2018 at 18:40
Feb 12, 2018 at 20:38 answer added Abdu Magdy timeline score: 0
Feb 12, 2018 at 18:57 comment added Abdu Magdy @PeterHeinig But if $F=R$, there is no square root of negative numbers. Hence $D_kD_{k-1}$ must be greater than $0$. Am I missing something?
Feb 12, 2018 at 18:52 comment added Abdu Magdy @PeterHeinig I've done that because while pondering on the corollary I realized that for the corollary to be true $$b_{kk}= \pm \sqrt{\frac{D_k}{D_{k-1}}} $$ must be true (Implied from the related theorem in the same book). So, I had two versions of the same question.
Feb 12, 2018 at 18:46 comment added Abdu Magdy @AbdelmalekAbdesselam There is no such hypothesis. My reputations prevented me from uploading a picture of the whole theorem. But it's a theorem about decomposing a matrix into triangular factors.
Feb 12, 2018 at 18:45 comment added Peter Heinig @AbduMagdy: their signs are the same; it is irritating all the same that the title does not agree with the OP.
Feb 12, 2018 at 18:42 comment added Abdelmalek Abdesselam there is probably a missing hypothesis here like the matrix is positive definite.
Feb 12, 2018 at 18:42 comment added Abdu Magdy @PeterHeinig They're pretty much the same. Either one implies the other.
Feb 12, 2018 at 18:41 comment added Abdu Magdy @AbdelmalekAbdesselam Then, is the corollary wrong?
Feb 12, 2018 at 18:41 comment added Peter Heinig @Abdu Magdy: the $\frac{D_k}{D_{k-1}}$ does not agree with the $D_kD_{k-1}$ in the OP.
Feb 12, 2018 at 18:39 comment added Abdelmalek Abdesselam no. just take a diagonal matrix.
Feb 12, 2018 at 18:25 review First posts
Feb 12, 2018 at 18:43
Feb 12, 2018 at 18:21 history asked Abdu Magdy CC BY-SA 3.0