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Feb 14, 2018 at 12:55 vote accept Thomas Rot
Feb 13, 2018 at 9:06 comment added Thomas Rot I should know better than to comment during my commute. I just accepted that the time-1 map would be a section. Anyway, the corrected answer is still very nice. It gives me an easy class of examples where I can play with. I'll leave the question open longer to see if there are other ideas.
Feb 13, 2018 at 2:05 comment added Ryan Budney To extend John's comment, the map $Diff(M) \to M$ extends to maps $Diff(M) \to C_n(M)$ and $Diff(M) \to Emb(X,M)$. In the first case you restrict the diffeomorphisms to a finite subset of $M$, in the second case you restrict the diffeomorphisms to a submanifold. Often these maps are informative.
Feb 13, 2018 at 0:37 comment added John Klein Duh...I was a trigger happy when I wrote the above. A flow doesn't suffice. However, when $M$ is a Lie group there is a section.
Feb 13, 2018 at 0:32 history edited John Klein CC BY-SA 3.0
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Feb 12, 2018 at 23:51 comment added Michael Albanese @DylanWilson: Ah, I missed that assumption. My bad.
Feb 12, 2018 at 22:45 comment added Dylan Wilson (@MichaelAlbanese that's not a counterexample to his claim because $S^2$ has no nonvanishing vector field... also, his claim holds whenever $M$ is itself a group, and for $S^7$, so the first sphere which could give a counterexample is $S^9$. That said- I still don't understand why the claim should be true.)
Feb 12, 2018 at 19:59 comment added Michael Albanese I don't think your claim that the cohomology of $M$ injects into the cohomology of $\operatorname{Diff}(M)$ is true. Smale showed thay $\operatorname{Diff}(S^2)$ is homotopy equivalent to $O(3)$, and $H^2(S^2; \mathbb{Z}) \cong \mathbb{Z}$ while $H^2(O(3); \mathbb{Z}) \cong H^2(\mathbb{RP}^3\sqcup\mathbb{RP}^3; \mathbb{Z}) = \mathbb{Z}_2\oplus\mathbb{Z}_2$, so the cohomology does not inject.
Feb 12, 2018 at 19:11 comment added Oscar Randal-Williams I don't believe this. To what diffeomorphism does your section send $x \in M$?
Feb 12, 2018 at 19:11 comment added Dylan Wilson I’m probably missing something silly, but how does a flow define a section? I can see how to define a map from R to Diff(M) or a map from M to Map(R,M), but I don’t see a map from M to Diff(M).
Feb 12, 2018 at 17:55 comment added Thomas Rot Excellent, this is exactly the type of answer that I was hoping for! I'll leave the question open for a bit longer, but I am already very happy!
Feb 12, 2018 at 17:29 history answered John Klein CC BY-SA 3.0