Timeline for Question on Hessian of a function (probability question)
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
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| S Feb 20, 2018 at 9:45 | history | bounty ended | CommunityBot | ||
| S Feb 20, 2018 at 9:45 | history | notice removed | CommunityBot | ||
| Feb 16, 2018 at 21:50 | vote | accept | CommunityBot | ||
| Feb 12, 2018 at 8:37 | answer | added | RaphaelB4 | timeline score: 1 | |
| S Feb 12, 2018 at 7:46 | history | bounty started | CommunityBot | ||
| S Feb 12, 2018 at 7:46 | history | notice added | user31317 | Improve details | |
| Feb 10, 2018 at 5:38 | comment | added | user31317 | Nice start Nate. | |
| Feb 10, 2018 at 5:35 | history | edited | user31317 | CC BY-SA 3.0 |
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| Feb 10, 2018 at 5:18 | comment | added | Nate Eldredge | If $f$ is three times continuously differentiable, then the Hessian $Hf$ is a $C^1$ map from $\mathbb{R}^n$ into $\mathbb{R}^{n^2}$, so its image has Hausdorff dimension $n$ and hence Lebesgue measure zero. In particular $Hg$ is everywhere nonzero with probability one, which is a start. But if $Hf$ is merely continuous then it seems like we could get some bad behavior. | |
| Feb 10, 2018 at 4:54 | answer | added | Igor Rivin | timeline score: 1 | |
| Feb 10, 2018 at 1:22 | comment | added | user31317 | Fixed, thank you! | |
| Feb 10, 2018 at 1:17 | history | edited | user31317 | CC BY-SA 3.0 |
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| Feb 10, 2018 at 0:43 | comment | added | Nate Eldredge | The Hessian of $f'$, I guess you mean? (Can we call it something that looks less like a derivative?) | |
| Feb 9, 2018 at 23:53 | history | asked | user31317 | CC BY-SA 3.0 |