Skip to main content
4 events
when toggle format what by license comment
Aug 8, 2018 at 21:17 comment added Todd Trimble @DuchampGérardH.E. Yes, I assume $f, g$ preserve all distributive lattice structure: meets and joins (and also empty meets and joins if those are considered as part of the definition of lattice). The point is that the inequality $(a \wedge b) \vee (c \wedge d) \leq (a \vee c) \wedge (b \vee d)$ typically isn't an equality, as one can easily see by putting the right side in disjunctive normal form, or using Venn diagrams, etc.
Aug 8, 2018 at 20:15 comment added Duchamp Gérard H. E. @ToddTrimble For your first equality, you suppose $f,g$ to preserve meets, am I right ? Otherwise, Dominic's lattice property is all right (it is a sublattice of the lattice product $L^P$).
Feb 9, 2018 at 14:39 comment added Todd Trimble Yes, but I think OP is looking not just at poset maps $L_1 \to L_2$, but at maps that preserve finite meets and joins. It's not true that your pointwise definition for $f \vee g$ gives a distributive lattice map, because $(f \vee g)(x \wedge y) = (f(x) \wedge f(y)) \vee (g(x) \wedge g(y))$ does not match $(f(x) \vee g(x)) \wedge (f(y) \vee g(y))$.
Feb 9, 2018 at 13:59 history answered Dominic van der Zypen CC BY-SA 3.0