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Feb 6, 2018 at 17:31 comment added Mateusz Wasilewski Actually, the complement of that, consisting of coefficients of weakly mixing representations, is an ideal.
Feb 6, 2018 at 16:14 comment added Yemon Choi No, for the following elementary reason: $F$ contains the trivial representation, and so $A_F(G)$ contains the constant function $1$. (This does not need the result of Runde and Spronk which you quote)
Feb 6, 2018 at 15:37 history asked Albert harold CC BY-SA 3.0