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Sep 11, 2019 at 15:42 comment added QcH @TheoJohnson-Freyd Do you mind sharing the formula in terms of "sums over diagrams" mentioned at the end of your answer? A reference would also be great! Thanks!
Feb 6, 2018 at 21:59 comment added Theo Johnson-Freyd @DanPetersen Could be. I only understand things in characteristic zero.
Feb 5, 2018 at 19:10 comment added Dan Petersen @Theo Both maps are quasi-isomorphisms in general - I think you mean that neither $L_\infty$ nor $C_\infty$ are cofibrant.
Feb 5, 2018 at 17:55 comment added Theo Johnson-Freyd @DanPetersen I only understand things in characteristic zero. I could be mistaken, but I believe that in non-zero characteristic, neither map $C_\infty \to C$ nor $L_\infty\to L$ is a quasiisomorphism.
Feb 5, 2018 at 17:54 comment added Theo Johnson-Freyd @PavelSafronov You know this literature much better than I do, so I trust your namings. I have certainly seen the name "Boardman--Vogt tensor product" used for the operation on dg operads given by $(A\otimes B)(n) = A(n) \otimes B(n)$. This is the monoidal structure that I mean.
Feb 4, 2018 at 21:57 comment added Fernando Muro @DanPetersen I think that even $L_\infty$-algebras only work in characteristic 0.
Feb 4, 2018 at 18:20 comment added Pavel Safronov When you say the Boardman--Vogt tensor product, do you really mean the Hadamard tensor product? Is there a definition of the BV tensor product for operads in a non-Cartesian monoidal category?
Feb 4, 2018 at 17:42 comment added Dan Petersen Thanks! This only works over a field of characteristic zero, right? If there were a sum over trees formula, one could hope to verify the statement over the integers.
Feb 4, 2018 at 17:24 history answered Theo Johnson-Freyd CC BY-SA 3.0