Timeline for A map from a symmetric product of a curve to its Jacobian
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 4, 2018 at 18:24 | comment | added | Jason Starr | That is not locally trivial. That is what my comment was about. If you pullback the projective bundle by a general translation, it is a non-isomorphic projective bundle. | |
| Feb 4, 2018 at 18:23 | comment | added | Sasha | @user4231: I am not sure it is locally trivial, but each component, $C^{(n)} \times C^{(n)} \to J_n \times J_n$ and $J_n \times J_n \to J_0$, is locally trivial. | |
| Feb 4, 2018 at 17:53 | comment | added | user4231 | Maybe I should clarify my question. Arthur Mattuck, in his article “Picard bundle”, showed that $C^{(n)}\to J$ is a projective fiber bundle in the sense of en.m.wikipedia.org/wiki/Fiber_bundle. My question is, is the map that I gave a fiber bundle in that sense? | |
| Feb 4, 2018 at 17:42 | comment | added | Sasha | @user4231: Local triviality of what? | |
| Feb 4, 2018 at 17:37 | comment | added | user4231 | I see why the fiber is the product of two projective spaces, but why do we have local triviality? | |
| Feb 4, 2018 at 16:31 | history | answered | Sasha | CC BY-SA 3.0 |