Timeline for Special subalgebras of central simple algebras
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 23, 2010 at 10:07 | history | edited | Robin Chapman | CC BY-SA 2.5 |
minor corrections
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| Jun 23, 2010 at 9:54 | comment | added | carlos | Thanks. It was much easier than I expected! The center of A and B are both F because $Z(A) \otimes Z(B) = Z(A \otimes B) = F$ and so considering the dimensions of both sides we get $Z(A) = Z(B) = F.$ Thanks again. | |
| Jun 23, 2010 at 9:49 | vote | accept | carlos | ||
| Jun 23, 2010 at 9:22 | history | answered | Robin Chapman | CC BY-SA 2.5 |