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Jun 24, 2010 at 16:22 vote accept Daniel Pomerleano
Jun 23, 2010 at 16:50 comment added Daniel Pomerleano The calculations for C[x], x an odd variable is I believe as follows. As a Gerstenhaber algebra, HH*(C[x]) is isomorphic to C[b,y,x^2]/(b^2,y^2,yb,yx^2), where b is odd and y, x^2 are even classes. There is a non-trivial bracket {b(x^2n),x^2}= -4x^(2n+2) All other brackets with x^2 are zero. The only class that survives the second differential is then y and 1 giving the above answer.
Jun 23, 2010 at 16:15 comment added Daniel Pomerleano Thanks for clearing it up. I've been thinking about this a fair bit lately and it is indeed a bit tricky. I'm not sure if my calcs support the conjecture. I am fairly certain that if one uses the "compactly supported" Hochschild cohomology of the curved algebra B one gets C[y]/y^2. For space reasons I'll add the detail in a comment. There may be an issue with convergence of spectral sequence for the completed Hochschild homology complex but offhand I would expect the answer to be the same. Anyways, I'll think a little bit about this and then send you an email. Thanks again!
Jun 23, 2010 at 15:38 vote accept Daniel Pomerleano
Jun 23, 2010 at 17:19
Jun 23, 2010 at 7:48 history answered Ed Segal CC BY-SA 2.5