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Feb 2, 2018 at 6:46 comment added Shaull @Tarash Banakh - good suggestion. I added a reformulation, but your's is better. I'll revise later today. Thanks!
Feb 2, 2018 at 6:42 comment added Taras Banakh @Shaull Maybe you should add that $B$ is an open semialgebraic neighborhood of $A$?
Feb 2, 2018 at 6:40 comment added Shaull @Tarash Banakh - Ugh, yes, you're right of course, but that's cheating :) I'll reform the question, since what I want are sets that are "close" to the graph.
Feb 2, 2018 at 6:35 history answered Taras Banakh CC BY-SA 3.0