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Feb 1, 2018 at 9:44 comment added Peter Michor If (and, locally, only if) $f$ is the gradient of a function $g$, then the Jacobian of $f$ equals the Hessian of $g$ and is thus symmetric.
Jan 31, 2018 at 12:22 comment added gerw Not every Jacobian matrix is symmetric. Consider $f(x) = (x_2, 0)$.
Jan 31, 2018 at 10:35 review First posts
Jan 31, 2018 at 10:55
Jan 31, 2018 at 10:31 history answered Leven CC BY-SA 3.0