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Feb 1, 2018 at 17:27 history edited Tito Piezas III CC BY-SA 3.0
2003 paper
Feb 1, 2018 at 13:09 vote accept Tito Piezas III
Feb 1, 2018 at 10:39 answer added Jesús Guillera timeline score: 11
Jan 31, 2018 at 16:29 comment added Wolfgang And I guess no luck with $\beta(3)$ for level 5? - Who knows?
Jan 31, 2018 at 15:26 history edited Tito Piezas III CC BY-SA 3.0
Binomial
Jan 31, 2018 at 14:43 comment added Tito Piezas III @Wolfgang: Yes, for level $7$ and (n-1/2) type, I tried $\pi^4,1/\pi^4,$ and $\beta(4)$. Only $(10)$ popped up.
Jan 31, 2018 at 14:17 comment added Wolfgang Have you tried level 7 the (n-1/2) type with $\sum_{n=0}^{\infty} \frac{(-1)^{n}}{(2n+1)^4}$ (corresponding to G)?
Jan 31, 2018 at 13:37 comment added Tito Piezas III And there are no others for levels $5,\,7$ with $(\pm2^k)^{-n}$ for $k<16$ either. Sigh.
Jan 31, 2018 at 11:08 history edited Tito Piezas III CC BY-SA 3.0
Four other formulas
Jan 30, 2018 at 16:08 comment added Tito Piezas III A search using Mathematica's integer relations couldn't find analogous formulas for levels $9,11$ with $(\pm 2^k)^{-n}$ for $k<16$.
Jan 30, 2018 at 15:50 history edited Tito Piezas III CC BY-SA 3.0
Phrasing
Jan 30, 2018 at 14:16 history asked Tito Piezas III CC BY-SA 3.0