Timeline for On a pattern for upside-down Ramanujan pi formulas
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Feb 1, 2018 at 17:27 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
2003 paper
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Feb 1, 2018 at 13:09 | vote | accept | Tito Piezas III | ||
Feb 1, 2018 at 10:39 | answer | added | Jesús Guillera | timeline score: 11 | |
Jan 31, 2018 at 16:29 | comment | added | Wolfgang | And I guess no luck with $\beta(3)$ for level 5? - Who knows? | |
Jan 31, 2018 at 15:26 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Binomial
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Jan 31, 2018 at 14:43 | comment | added | Tito Piezas III | @Wolfgang: Yes, for level $7$ and (n-1/2) type, I tried $\pi^4,1/\pi^4,$ and $\beta(4)$. Only $(10)$ popped up. | |
Jan 31, 2018 at 14:17 | comment | added | Wolfgang | Have you tried level 7 the (n-1/2) type with $\sum_{n=0}^{\infty} \frac{(-1)^{n}}{(2n+1)^4}$ (corresponding to G)? | |
Jan 31, 2018 at 13:37 | comment | added | Tito Piezas III | And there are no others for levels $5,\,7$ with $(\pm2^k)^{-n}$ for $k<16$ either. Sigh. | |
Jan 31, 2018 at 11:08 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Four other formulas
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Jan 30, 2018 at 16:08 | comment | added | Tito Piezas III | A search using Mathematica's integer relations couldn't find analogous formulas for levels $9,11$ with $(\pm 2^k)^{-n}$ for $k<16$. | |
Jan 30, 2018 at 15:50 | history | edited | Tito Piezas III | CC BY-SA 3.0 |
Phrasing
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Jan 30, 2018 at 14:16 | history | asked | Tito Piezas III | CC BY-SA 3.0 |