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Feb 12, 2018 at 11:08 vote accept spin
Feb 1, 2018 at 12:21 comment added Geoff Robinson Ok, sorry to query unnecessarily, my oversight.
Feb 1, 2018 at 11:48 comment added Derek Holt Well ${\rm GL}(r,3)$ has an element of order $2$ in its centre, so the wreath product with $S_s$ contains an elementary abelian $2^s$ as normal subgroup. On passing to ${\rm PSL}(rs,3)$ we lose at most two of the factors from the $2^s$, so if $s \ge 3$ then there we have a nontrivial normal $2$-subgroup.
Jan 31, 2018 at 19:53 comment added spin What originally brought me to wonder about this question was Iwasawa's simplicity criterion: if $G$ is a finite group such that $G = [G,G]$ and $S$ is a primitive $G$-set such that $\operatorname{Stab}_G(x)$ has a normal solvable subgroup whose $G$-conjugates generate $G$, then $G$ is simple. So one could ask if there is a converse for this. Then we are basically asking for $G$ simple whether there exists a maximal subgroup $M$ of $G$ with a nontrivial normal solvable (equivalently nontrivial normal abelian) subgroup. This weaker statement holds, as noted in the comments by Geoff Robinson.
Jan 31, 2018 at 19:45 comment added spin A bit disappointing that the result is not true for all simple groups in the end, but thank you for the very nice answer.
Jan 31, 2018 at 17:08 comment added Nick Gill Except that I'm slightly unsure whether Gorenstein's result is for maximality over all 2-locals, or over all subgroups -- if the latter, then it would be a nice companion to yours... But I suspect it's the former....
Jan 31, 2018 at 17:08 comment added Nick Gill +1 for a lovely answer. I am reminded of Gorenstein's result about maximal 2-local subgroups: If $G$ is a simple group with only one conjugacy class of maximal 2-local subgroups, then $G$ is isomorphic to $L_2(2^n)$, $Sz(2^n)$ or $U_3(2^n)$ for some $n\geq 2$. (in his paper "On finite simple groups of characteristic 2 type"). This seems like the "next" set of simple groups to consider after the ones you've classified...
Jan 30, 2018 at 17:45 comment added Geoff Robinson Still a nice answer and a good question.
Jan 30, 2018 at 14:01 history edited Derek Holt CC BY-SA 3.0
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Jan 30, 2018 at 13:01 history edited Derek Holt CC BY-SA 3.0
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Jan 30, 2018 at 12:55 comment added Derek Holt @GeoffRobinson unfortunately I failed to check the small exceptional cases correctly, and I found a mistake. But I guess the corrected answer is also interesting.
Jan 30, 2018 at 12:54 history edited Derek Holt CC BY-SA 3.0
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Jan 30, 2018 at 11:11 comment added Geoff Robinson Very nice answer. This is indeed a surprising outcome, which I for one initially would not have expected, and which makes the question a really good one. I suppose in another sense it indicates that there are maximal subgroups of some simple groups which don't reflect very much about the group itself.
Jan 29, 2018 at 20:10 history edited Derek Holt CC BY-SA 3.0
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Jan 29, 2018 at 16:50 history answered Derek Holt CC BY-SA 3.0