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Jan 25, 2018 at 13:45 comment added Igor Rivin @aglearner Yes, I agree, it's not quite there.
Jan 25, 2018 at 9:10 comment added aglearner Igor, sorry I realized that the confusion probably happened because I had not given the definition of a "length decreasing homotopy". This is a homotopy such that for any $t_1<t_2$ the length of $\varphi_{t_2}(S^1)$ is smaller than the length $\varphi_{t_1}(S^1)$. You agree that in the present form your answer does not settle this question?
Jan 25, 2018 at 2:06 comment added Igor Rivin @aglearner each curve in the sequence is homotopic to any other one, same is true for any subsequence.
Jan 25, 2018 at 1:23 comment added aglearner Exactly, and my question is about a continuous homotopy, not about a sequence. I don't see how to get such a homotopy from what you propose
Jan 25, 2018 at 1:15 comment added Igor Rivin It does not need to converge. There will be a convergent subsequence whose length will go to the infimum.
Jan 25, 2018 at 0:55 comment added aglearner Igor, thanks. If you are speaking of Brikhoff shortening process, it is known that it does not need to converge: homepages.warwick.ac.uk/~masgak/papers/bhb-catone.pdf so I don't see why this will give you a continuous homotopy.
Jan 25, 2018 at 0:26 history answered Igor Rivin CC BY-SA 3.0