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Sep 22, 2018 at 19:01 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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May 30, 2018 at 22:00 comment added Pietro Majer A question: Do you take here as length of $\phi \in C^1(\mathbb{S}^1, M) $ its total variation $\int_{\mathbb{S}^1}|\phi'(s)| ds$, or the $\mathcal{H}^1$ measure of $\phi(\mathbb{S}^1)$? (This make a difference for non-injective curves).
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Jan 25, 2018 at 19:21 comment added John Pardon @IgorBelegradek it's just $\mathbb R$. The subscript indicates the name of the variable used as the coordinate of that factor.
Jan 25, 2018 at 19:04 comment added aglearner Igor, in this example the problem is located close to the geodesic $0\times S^1$, so one can easily make this example compact...
Jan 25, 2018 at 19:01 comment added Igor Belegradek @JohnPardon: what is $\mathbb R_s$? If it non-compact, that it is ruled out by compactness assumption on $M$.
Jan 25, 2018 at 18:13 comment added aglearner Thanks a lot John, indeed it looks as a counterexample...I have not thought carefully of what "locally minimizing" means for a geodesic...
Jan 25, 2018 at 17:09 comment added John Pardon It seems false to me. How about $M=\mathbb R_s\times S^1_t$ with metric $ds^2+(2-e^{-1/s^2}\cos(\frac 1s))dt^2$ as a probable counterexample. The central circle $\{0\}\times S^1$ is not locally length minimizing ($\{\frac 1{2\pi k}\}\times S^1$ has smaller length for any positive integer $k$). I would suspect there is no length decreasing homotopy starting at $\{0\}\times S^1$ (let alone one converging to a locally length minimizing curve).
Jan 25, 2018 at 9:09 history edited aglearner CC BY-SA 3.0
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Jan 25, 2018 at 0:57 history edited aglearner CC BY-SA 3.0
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Jan 25, 2018 at 0:26 answer added Igor Rivin timeline score: 1
Jan 25, 2018 at 0:19 comment added Igor Rivin Does a point qualify as locally length-minimizing?
Jan 24, 2018 at 20:18 history asked aglearner CC BY-SA 3.0