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Nov 19 at 20:03 history edited Anton Petrunin CC BY-SA 4.0
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Jan 24, 2018 at 18:54 history edited Anton Petrunin CC BY-SA 3.0
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Jan 24, 2018 at 7:05 comment added erz @MateuszKwaśnicki I think it would help if you elaborated on why this is the case and why the set of points such that the maximal ball touches $\partial\Omega$ in a different way has measure zero.
Jan 23, 2018 at 19:12 comment added Mateusz Kwaśnicki To be specific: $|\nabla \operatorname{dist}_{\partial \Omega}(x_0)| = 1$ if the maximal ball $B(x_0, r)$ contained in $\Omega$ touches the boundary of $\Omega$ at one point only.
Jan 23, 2018 at 17:53 history edited Anton Petrunin CC BY-SA 3.0
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Jan 23, 2018 at 17:46 history answered Anton Petrunin CC BY-SA 3.0