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Jan 27, 2018 at 22:39 vote accept 0xbadf00d
Jan 23, 2018 at 16:54 comment added 0xbadf00d @YemonChoi It's fine for me to assume that $E$ has the approximation property; but he doesn't make this assumption.
Jan 23, 2018 at 16:53 comment added 0xbadf00d @YemonChoi I've found the claim in the book Semimartingales: A Course on Stochastic Processes by Michel Métivier on page 138. As I indicated in the question, I thought he means that $E\:\hat\otimes_\pi\:E$ is embedded into $\mathfrak B(E'\times E')$.
Jan 23, 2018 at 16:02 answer added Matthew Daws timeline score: 2
Jan 23, 2018 at 10:02 answer added Jochen Wengenroth timeline score: 5
Jan 22, 2018 at 23:32 comment added Yemon Choi Secondly, my immediate instinct is to worry if something goes wrong when E does not have the approximation property
Jan 22, 2018 at 23:32 comment added Yemon Choi Just to clarify: you are not trying to prove that $E\hat\otimes_\pi E$ is isomorphic to a closed subspace of ${\rm Bil}(E' \times E')$ are you?
Jan 22, 2018 at 15:13 history asked 0xbadf00d CC BY-SA 3.0