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Jan 15, 2018 at 13:55 comment added Alexandre Eremenko It is equal: when $w$ is the fundamental state of the first equation (which I wrote), $y$ is the fundamental state of the second. The fundamental state is characterized by two properties: it belongs to $L^2$ and has no changes of sign. Of course, the $\lambda_0$ of YOUR equation is $\geq$ my $\lambda_0(\epsilon)$.
Jan 14, 2018 at 16:31 comment added char Thank you for this answer. I just have one question: didn't you mean $\lambda_0(\epsilon) \geq \epsilon^{\frac{2}{3}} \lambda_0(1)$ instead of equals (I don't see how to show the equality)?
Jan 14, 2018 at 15:28 vote accept char
Jan 14, 2018 at 14:27 history answered Alexandre Eremenko CC BY-SA 3.0