Timeline for Characterizing 1-ended graphs
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Jan 14, 2018 at 9:39 | vote | accept | I. Haage | ||
Jan 13, 2018 at 21:52 | comment | added | Taras Banakh | The implication 2 $\Rightarrow$ 1 also is simple: just observe that for any finite connected subgraph $\Gamma$ of a 1-ended graph $G$ the complement $G\setminus\Gamma$ has finitely many connected components and exactly one of them is infinite. Using this fact, by induction, one can easily construct the required infinite path in $G$. | |
Jan 13, 2018 at 21:45 | answer | added | Lee Mosher | timeline score: 4 | |
Jan 13, 2018 at 20:28 | history | edited | YCor |
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Jan 13, 2018 at 20:26 | comment | added | YCor | Maybe you could mention that clearly 1 implies 2, so you want to know about the converse. | |
Jan 13, 2018 at 19:57 | comment | added | I. Haage | Thanks for pointing this out, I edited to add the assumption of connectedness. | |
Jan 13, 2018 at 19:57 | history | edited | I. Haage | CC BY-SA 3.0 |
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Jan 13, 2018 at 19:51 | comment | added | Arun Debray | No. Let $G$ be a graph with a vertex for every natural number and an edge between $n$ and $n+1$ for all $n$, and let $G_+$ denote $G$ together with an additional, isolated vertex. Then, $G_+$ is 1-ended, but there's no path that reaches all vertices of $G_+$. | |
Jan 13, 2018 at 19:46 | review | First posts | |||
Jan 13, 2018 at 19:52 | |||||
Jan 13, 2018 at 19:42 | history | asked | I. Haage | CC BY-SA 3.0 |