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Apr 13, 2019 at 4:03 comment added LSpice I think that your definition of (pseudo-)reflection is non-standard, since it doesn't include the usual finite-order condition.
Jun 24, 2010 at 8:54 comment added Bugs Bunny Steve: I think so. The reflection rep is determined by the diagram, diagram automorphism does not change the data that determines it.
Jun 23, 2010 at 18:01 comment added GS Arminius: For non-faithful rep's $G$, T. Chmutova has written this paper: arxiv.org/abs/math/0505653 I think she will have something to say about what you're interested in.
Jun 23, 2010 at 10:19 comment added GS Bugs: Interesting! Is it obvious that should be so?
Jun 23, 2010 at 7:08 comment added Bugs Bunny Hey, Steve! I think I have gone slightly bonkers with my comment: twisting by the outer automorphism does not change to reflection representation. I see it is true, in general: twist by a diagram automorphism is not changing the reflection representation of the Coxeter group.
Jun 22, 2010 at 12:15 history edited user717 CC BY-SA 2.5
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Jun 22, 2010 at 11:13 comment added GS You're absolutely right! That observation (that reflection groups are precisely those with polynomial invariants) really was important.
Jun 22, 2010 at 11:10 comment added Victor Protsak I just want to point out that the point of Shephard-Todd was not classification, rather it was the Chevalley-Shephard-Todd theorem. Since their proof is case-by-case, they listed complex reflection groups and so their paper became a convenient reference.
Jun 22, 2010 at 10:24 comment added GS ...though Shephard-Todd probably gets more credit for completing the classification than is really deserved. Most of the work had been done, I believe, by the time that paper was written---especially for the classification of the primitive groups.
Jun 22, 2010 at 10:17 comment added GS ..also, if we're identifying things up to automorphisms coming from GL(V), the question is much less interesting (and in fact, Arminius gave the answer in the text of the question).
Jun 22, 2010 at 10:04 comment added GS Hiya Bugs, For W(B2) at least they are not different. The group of outer automorphisms may well fix rep'ns occasionally.
Jun 22, 2010 at 9:59 comment added Bugs Bunny The difference between these definitions is in outer automorphisms. Arminius identifies twists by outer automorphisms, while Stephen does not. Say, take the dihedral group with even edge: it has two standard reflection representations, different by outer twist. In Arminius' world they are the same and in Stephen's they are different.
Jun 22, 2010 at 9:50 answer added Bugs Bunny timeline score: 3
Jun 22, 2010 at 9:13 comment added GS I don't have Kane's book to hand, but it seems likely to me that he introduces this definition in order to discuss the classification of subgroups of GL(V) up to conjugacy---which is really a different from classifying representations of a particular group up to isomorphism! The latter is a finer (fewer elements in each equivalence class) classification, and more interesting/difficult.
Jun 22, 2010 at 9:07 comment added user717 Good question. I don't know. I came across this definition in "Reflection groups and invariant theory" by Richard Kane (p. 156). But he's not really using this concept...
Jun 22, 2010 at 9:04 comment added GS Your definition of isomorphism of representations is somewhat different from usual no? Normally one would require an elementwise compatibility $f \rho(g) f^{-1}=\rho'(g)$ for all $g \in G$.
Jun 22, 2010 at 8:46 answer added Bruce Westbury timeline score: 3
Jun 22, 2010 at 8:38 history asked user717 CC BY-SA 2.5