Timeline for the asymptotic behaviour of function as $\lambda \to -\infty$
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jan 15, 2018 at 0:25 | vote | accept | Kerr | ||
| Jan 13, 2018 at 20:01 | answer | added | Christian Remling | timeline score: 3 | |
| Jan 13, 2018 at 5:14 | comment | added | user64494 | Maple explicitly solves $y'(x)=-y(x)^2-V(x)-\lambda+1$ for concrete $V(x)$, e.g. $\sin(x),\,\exp(x)$. This may be useful for you as model examples. | |
| Jan 13, 2018 at 1:06 | comment | added | Kerr | @BrendanMcKay that's true, but it still seems to be hard to study the behaviour of $y(x)$ in this context, since as $\lambda \to -\infty$, $y'(x)$ depends on $-y(x)^2-\lambda$, and the latter expression is probably not good for analysis | |
| Jan 13, 2018 at 1:01 | comment | added | Brendan McKay | If $y(x)=u'(x)/u(x)$, then $y(x)$ satisfies $y'(x)=-y(x)^2-V(x)-\lambda+1$, apparently. | |
| Jan 12, 2018 at 23:46 | history | edited | YCor |
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| Jan 12, 2018 at 22:53 | history | asked | Kerr | CC BY-SA 3.0 |