Timeline for Increasing sequences in polynomial progressions modulo p
Current License: CC BY-SA 3.0
5 events
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Jan 16, 2018 at 6:04 | history | edited | Ryan Alweiss |
add number theory tag
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Jan 13, 2018 at 15:48 | comment | added | Ryan Alweiss | Good catch, although your comment only applies to the squares case. For squares I think $L(p)$ is bigger, because for instance we can use the squares of everything up to $d\sqrt{p}$ and then we expect a $2\sqrt{p(1-d^2)}$ increasing sequence left that is compatible with this. This can yield anything up to $\sqrt{5p}$ although empirical evidence suggests $\sqrt{6p}$ is the answer. For inverses, cubes, fourth powers, and so on, empirical evidence suggests it appears to approach $2\sqrt{p}$. I am pretty sure that squares are the only exceptional case. | |
Jan 13, 2018 at 1:40 | comment | added | Colin Defant | I don't think these sequences will give pseudorandom "permutations" because of the "local linearity" you mentioned. Let $L(p)$ be the length $k$ that you are considering. I just computed $L(p)$ for the first $3000$ primes, and it appears as though $L(p)$ is not $(2+o(1))\sqrt p$. In fact, it looks like $\liminf_{p\to\infty}\frac{1}{\sqrt p}L(p)>2.2$. You might try thinking about the sequences explicitly rather than probabilistically, at least in trying to construct long increasing subsequences to give lower bounds for $L(p)$. Probabilistic arguments might still help in finding upper bounds. | |
Jan 12, 2018 at 20:23 | review | First posts | |||
Jan 12, 2018 at 20:38 | |||||
Jan 12, 2018 at 20:19 | history | asked | Ryan Alweiss | CC BY-SA 3.0 |