Skip to main content

Timeline for Locally Riemannian Connection

Current License: CC BY-SA 3.0

15 events
when toggle format what by license comment
Jan 18, 2018 at 11:51 vote accept Aureliano Skirzewski
Jan 17, 2018 at 14:36 answer added Robert Bryant timeline score: 15
Jan 15, 2018 at 14:46 comment added Aureliano Skirzewski The condition $g_{ap}R^p{}_{bcd} + g_{bp}R^p{}_{acd} = 0$ can be rewritten as $\delta^{(p}_{(a}R^{q)}{}_{b)cd} g_{pq} = 0,$ a collection of matrices labeled by $c$ and $d$ with the same kernel... is there a way to identify the existence of a common eigenvector with null eigenvalue?
Jan 13, 2018 at 21:32 comment added Deane Yang It suffices to but doesn't appear to be easy to solve the following two equations: $\partial_cg_{ab} = g_{ap}\Gamma^p_{cb} + g_{bp}\Gamma^p_{ac}$ and $g_{ap}R^p{}_{bcd} + g_{bp}R^p{}_{acd} = 0$. Indeed, additional conditions on the curvature tensor and its covariant derivatives are probably needed.
Jan 13, 2018 at 21:29 comment added Deane Yang Sorry, but I didn't think this through. Now that I've done a little bit of calculation, this looks like an overdetermined system of PDEs that isn't easy for me to analyze.
Jan 12, 2018 at 18:41 comment added Aureliano Skirzewski I really want to understand that argument @DeaneYang, could you suggest some literature? or explain a little more... I do not understand that article about parallel sections
Jan 12, 2018 at 17:39 comment added Ben McKay You could employ the holonomy group in an arbitrarily small open set, which would already give a nontrivial condition, locally but not infinitesimally.
Jan 12, 2018 at 17:34 comment added Deane Yang Note that $dg_{ab} = (g_{ap}\Gamma^p_{bc} + g_{bp}\Gamma^p_{ac})\,dx^c$, so you can use the Frobenius theorem.
Jan 12, 2018 at 17:31 comment added Aureliano Skirzewski Within that article, Richard Atkins (the author) argues that the local problem has been previously solved by means of constructing a derived flag and refers to arxiv.org/pdf/0804.1732.pdf . This last article says "We consider when a smooth vector bundle endowed with a connection possesses non-trivial, local parallel sections. This is accomplished by means of a derived flag of subsets of the bundle. The procedure is algebraic and rests upon the Frobenius Theorem." Is that the question I made?
Jan 12, 2018 at 17:16 comment added j.c. That question is not the same as yours, but unless I am misunderstanding something, I believe several of the answers and references will be helpful to you. See e.g. arxiv.org/abs/0804.2698 cited in John's answer mathoverflow.net/a/173399
Jan 12, 2018 at 17:03 comment added Aureliano Skirzewski That question is concerned with the existence of a metric, is that strictly the same question?
Jan 12, 2018 at 16:59 comment added j.c. This question is related mathoverflow.net/questions/54434
Jan 12, 2018 at 16:51 comment added Aureliano Skirzewski Nevermind the existence of a unique metric tensor on the whole manifold
Jan 12, 2018 at 16:43 comment added Aureliano Skirzewski Non local information as the holonomy group is not accessible so I wish to restrict to what can we know locally
Jan 12, 2018 at 16:42 history asked Aureliano Skirzewski CC BY-SA 3.0