Timeline for What is the degree zero Gromov-Witten invariant of quintic threefold?
Current License: CC BY-SA 3.0
6 events
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Jan 31, 2018 at 7:04 | comment | added | keaton | Thank you for Jason and Honglu and I'm sorry for my late reply. I also found a good reference for degree zero Gromov-Witten invariant written by R. Pandharipande : arxiv.org/abs/math/0302077 | |
Jan 9, 2018 at 22:02 | comment | added | Honglu | In addition to Jason's comments, when $g\geq 2$, $\overline M_{g,0}(X,0)=\overline M_{g}\times X$. The obstruction bundle is given by $\mathbb E^\vee \boxtimes TX$ where $\mathbb E$ is the hodge bundle. Then I believe a splitting principle computation plus a little intersection theory on $\overline M_g$ should give you the result. When $g=1$ you need one marking, and the computation follows from the similar idea. | |
Jan 9, 2018 at 20:43 | comment | added | Jason Starr | Typo correction: "... stable maps to $X$ is an empty stack." --> " ... stable maps to $X$ with zero homology class is an empty stack." | |
Jan 9, 2018 at 18:13 | comment | added | Jason Starr | For every complex manifold $X$, the moduli stack of genus-$0$, $0$-pointed stable maps to $X$ is an empty stack. Thus, it is (tautologically) transverse, the virtual fundamental class equals the actual fundamental class, this is the zero class, and every pairing of this fundamental class against cohomology classes is zero. | |
Jan 9, 2018 at 15:06 | history | edited | Martin Sleziak | CC BY-SA 3.0 |
capitalization
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Jan 9, 2018 at 14:45 | history | asked | keaton | CC BY-SA 3.0 |