Timeline for Is ${\rm lcm}\{{\rm ord}_p(q)\colon q\mid p-1,\ q>2\}>\sqrt p\ \,$?
Current License: CC BY-SA 3.0
14 events
when toggle format | what | by | license | comment | |
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Jan 10, 2018 at 1:52 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
edited body
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Jan 10, 2018 at 1:32 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
sorry for multiple edits, the lemma 1 was incorrectly stated. It has less strength than before. Halberstam is not required.
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Jan 9, 2018 at 22:00 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
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Jan 9, 2018 at 21:21 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
much more detail is required for the lemma 1
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Jan 9, 2018 at 18:55 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
edited body
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Jan 9, 2018 at 18:46 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
argument simplified by Bombieri-Vinogradov, but it should also include Halberstan's result on p-1.
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Jan 9, 2018 at 8:19 | comment | added | Sungjin Kim | The estimate is weak for answering your question, but it shows that for most of primes $5$ mod $8$, $M_p$ is larger than $\sqrt p$. | |
Jan 9, 2018 at 8:17 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
1<q has to be imposed
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Jan 9, 2018 at 7:16 | comment | added | Seva | Does not quite answer the question, but impressive technology, anyway! | |
Jan 9, 2018 at 6:28 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
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Jan 9, 2018 at 6:16 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
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Jan 9, 2018 at 5:06 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
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Jan 9, 2018 at 4:09 | history | edited | Sungjin Kim | CC BY-SA 3.0 |
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Jan 9, 2018 at 2:21 | history | answered | Sungjin Kim | CC BY-SA 3.0 |