Timeline for Capacity and measure
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Jan 7, 2018 at 3:10 | comment | added | Nirav | @NateEldredge Oh yeah, because $\mu_c(F)=\mu_c(\mathbb{R}^2)>0$. Thanks. | |
| Jan 7, 2018 at 2:56 | comment | added | Nate Eldredge | Accidentally deleted my earlier comment, but doesn't the same argument still work? If $F$ has zero capacity then it has empty interior, so $\mu(\partial F) = \mu(\overline{F}) \ge \mu(F) \ge \mu_c(F) > 0$. | |
| Jan 7, 2018 at 2:54 | comment | added | Nate Eldredge | Ok. I don't think that places any restrictions on $\mu$ since every finite measure is a weak limit of smooth measures (e.g. by convolution). | |
| Jan 7, 2018 at 2:28 | comment | added | Nirav | @NateEldredge The only other information that we have about $\mu_m$ is that each one is diffuse with respect to $p\text{-cap}$. | |
| Jan 7, 2018 at 2:27 | history | edited | Nirav | CC BY-SA 3.0 |
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| Jan 7, 2018 at 2:19 | comment | added | Nirav | @NateEldredge Apologies for the typo, the $\mu$ in (1) was meant to be $\mu_c$. I have fixed this. | |
| Jan 7, 2018 at 2:16 | history | edited | Nirav | CC BY-SA 3.0 |
added 2 characters in body
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| Jan 6, 2018 at 23:48 | history | asked | Nirav | CC BY-SA 3.0 |