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Aug 15, 2021 at 17:26 comment added Tomasz Kania You may find this useful arxiv.org/abs/2102.03838
Jan 7, 2018 at 23:23 vote accept M10687
Jan 7, 2018 at 23:09 answer added Yemon Choi timeline score: 6
Jan 5, 2018 at 5:12 comment added M10687 @YemonChoi thank you, that certainly exposes the error.
Jan 5, 2018 at 4:49 comment added Yemon Choi My previous comment had an embarrassing mistake, and I now think that your first claim is not justified (as you yourself suspected). The point is that althoug $X/\ker T$ injects continuously into something separable, that doesn't necessarily mean it is separable. Consider $\ell_\infty \to c_0$ obtained by multiplying the $n$th entry with $1/n$.
Jan 5, 2018 at 3:19 comment added M10687 If $X$ is reflexive, then $X$ is the dual of a Banach space. It is a theorem of Argyros, Dodos and Kanellopolous that every dual of a Banach space has separable quotient: users.uoa.gr/~pdodos/Publications/13-Unconditional.pdf
Jan 5, 2018 at 2:56 comment added Yemon Choi Why is it true that "if $X$ is reflexive we are done"?
Jan 5, 2018 at 2:53 history edited Martin Sleziak CC BY-SA 3.0
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Jan 5, 2018 at 2:45 review First posts
Jan 5, 2018 at 3:45
Jan 5, 2018 at 2:42 history asked M10687 CC BY-SA 3.0