Skip to main content

Timeline for Schauder basis $L^p(\mathbb{R})$

Current License: CC BY-SA 3.0

4 events
when toggle format what by license comment
Jan 4, 2018 at 13:08 comment added Bill Johnson A uniformly bounded orthonormal system that is unconditional in $L^p$ must be equivalent to the unit vector basis of $\ell^2$ (e.g., use type-ecotype theory), so a basis of characters cannot be unconditional. Therefore there is a permutation of any character basis for $L^p$ that is not a basis for $L^p$ when $p\not=2$.
Jan 3, 2018 at 23:19 comment added Fedor Petrov Trigonometric system is a Schauder basis for all $L^p,p>1$. Probably we may check other specific example like Walsh.
Jan 3, 2018 at 21:38 comment added Nebojša Đurić And for some p>1?
Jan 3, 2018 at 21:06 history answered Fedor Petrov CC BY-SA 3.0