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Aug 3, 2010 at 10:10 vote accept JGis
Jun 22, 2010 at 0:50 comment added Victor Protsak Another problem with the even case is that $SO_4$ is not simple as an algebraic group: it is isogenuous to $SO_3\times SO_3.$
Jun 21, 2010 at 20:55 vote accept JGis
Jun 21, 2010 at 21:51
Jun 21, 2010 at 20:40 answer added Jim Humphreys timeline score: 4
Jun 21, 2010 at 20:36 vote accept JGis
Jun 21, 2010 at 20:37
Jun 21, 2010 at 20:36 vote accept JGis
Jun 21, 2010 at 20:36
Jun 21, 2010 at 20:34 answer added Skip timeline score: 5
Jun 21, 2010 at 20:24 answer added Torsten Ekedahl timeline score: 2
Jun 21, 2010 at 20:01 history edited JGis CC BY-SA 2.5
edited body; added 20 characters in body
Jun 21, 2010 at 19:45 answer added Charles Matthews timeline score: 1
Jun 21, 2010 at 19:43 comment added Torsten Ekedahl (I presume you mean $A\in\mathrm{SL}_n(\mathbb C)$.) When $n$ is even the group has non-trivial centre and hence is not simple but that is the only problem. Generally results on normal subgroups of semi-simple groups is due to Tits but this particular case may be earlier.
Jun 21, 2010 at 19:42 comment added Ryan Reich That's $O_n(\mathbb{C})$ you've defined. You should write $A \in SL_n(\mathbb{C})$ (otherwise there's an obvious normal subgroup :)).
Jun 21, 2010 at 19:32 history asked JGis CC BY-SA 2.5