Timeline for Are there natural choices of $\sqrt{-1}$ in $\mathbb Z/p\mathbb Z$ for a prime $p\equiv 1\pmod 4$
Current License: CC BY-SA 2.5
3 events
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| Mar 12 at 23:42 | comment | added | GH from MO | This explicit formula came handy in my response here (where I also included a proof of the formula, based on Jacobi sums): mathoverflow.net/questions/466706 | |
| Jun 21, 2010 at 21:17 | comment | added | Victor Protsak | If I remember correctly, his proof was based on quartic Gauss sums. Of course, the main feature of this formula is an explicit value of $a$. You are still using $\sqrt{-1}=(2n)!$ to get $b.$ | |
| Jun 21, 2010 at 15:24 | history | answered | Péter Komjáth | CC BY-SA 2.5 |