I'm confused and probably have a thinking error. Exercise 6 on page 420 of Lam's Lectures on Modules and Rings says essentially:
Let $R$ be a ring and $C$ a cyclic right $R$-module: $C=R/A$ with some right ideal $A$ in R. Let $(-)^{*}$ denote the functor $Hom_R(-,R)$$\operatorname{Hom}_R(-,R)$. Then $C^{*} \cong ann_l(A)$$C^{*} \cong \operatorname{ann}_l(A)$ as right R$R$-modules.
I would think that this is correct.
Specialising to a $A=J$ being the Jacobson radical this gives: $C^{*} \cong ann_l(J) \cong soc(R)$$C^{*} \cong \operatorname{ann}_l(J) \cong \operatorname{soc}(R)$ as the left annihilator of the Jacobson radical is the socle of the algebra (seealgebra; see Lemma 8.3 of Landrock's Finite Group Algebras and Their Modules). So Exercise 6 tells us that taking duals of simple modules gives again simple modules. In particular, the double dual of a simple module should again be the direct sum of simple modules?!
Now take $R$ to be a local non-selfinjective algebra and $C=R/J$ (which is the unique right simple $R$-module). Let $S$ be the simple left $R$-module. Then we get $C^{*} \cong soc(R) \cong \oplus_{k=1}^{n}{S}$$$C^{*} \cong \operatorname{soc}(R) \cong \bigoplus_{k=1}^{n}{S}$$ for some $n$. Then we get doing the same again, $C^{**} \cong {\oplus}_{k=1}^{m}{C}$ for some $m$. But taking for example the algebra $R=K\langle x,y\rangle / (x^2,y^2,xy)$,$$R=K\langle x,y\rangle / (x^2,y^2,xy),$$ my computer tells me that $C^{**}$ is not semisimple and has an indecomposable direct summand of dimension 2.
I do not see the mistake at the moment, so maybe lemmaLemma 8.3. in the book of Landrock might be wrong?