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Dec 29, 2017 at 5:54 history edited YCor
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Dec 29, 2017 at 4:42 vote accept Minji Kim
Dec 29, 2017 at 3:49 history edited Minji Kim CC BY-SA 3.0
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Dec 28, 2017 at 9:31 answer added Aaron Meyerowitz timeline score: 3
Dec 28, 2017 at 4:16 comment added Gerry Myerson OK, that's an example where you can reduce the rank by more than 1 (a simpler example would be $$\pmatrix{1&0&0\cr0&2&0\cr0&0&3\cr}$$ but what about in general?
Dec 28, 2017 at 2:28 comment added Minji Kim 1) For example, think of the matrix $\begin{bmatrix} 2 &2& 1\\ 2 & 6 & 2\\1 & 2 & 4\end{bmatrix}$. We cannot reduce its rank more than one by just substracting $\lambda I$, but if we substract $\begin{bmatrix} 1 &0& 0\\ 0 & 2 & 0\\0 & 0 & 3\end{bmatrix}$, we can reduce the rank by 2. 2) Yes, but I am especially interested in the case where $Q$ is positive definite.
Dec 27, 2017 at 19:45 answer added Alexandre Eremenko timeline score: 4
Dec 27, 2017 at 16:05 comment added Gerry Myerson Good question. But, 1) is there any reason to think that, in general, you can reduce the rank by more than 1? 2) why the restriction to positive definite matrices? isn't the question of interest for all matrices?
Dec 27, 2017 at 12:36 review First posts
Dec 27, 2017 at 12:38
Dec 27, 2017 at 12:34 history asked Minji Kim CC BY-SA 3.0