Timeline for first-order definability transitive closure operator
Current License: CC BY-SA 2.5
4 events
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Mar 17, 2013 at 0:48 | comment | added | Andreas Blass | That covers, in particular, the definition of $V_\alpha$ and the definition if iterated unions that leads (as in Joel's answer) to $TC$. Once one has $TC$, it can serve as the $H$ for definitions by $\in$-recursion. [Technical note: By using a definable function $H$ instead of a "predecessor" relation, I've built in the assumption that $H(x)$ is always a set, which otherwise would have to be added. Also, if $G$ and $H$ are $\Delta_1^{ZF}$-definable, then so is $F$; $\Delta_1^{ZF}$-definability cannot be replaced here with $\Delta_1^{ZF}$-definability of the predecessor relation.] | |
Mar 17, 2013 at 0:42 | comment | added | Andreas Blass | Although "turning recursive definitions into explicit definitions may not be possible" is true, a very broad class of recursive definitions can be made explicit. Specifically, if $F$ is defined recursively by $F(x)=G(x,F\upharpoonright H(x))$ where $G$ and $H$ are definable in ZFC and where $H$ is well-founded (in the sense that every nonempty set $u$ has an element $x$ with $H(x)\cap u=\varnothing$), then $F$ admits an explicit definition in ZFC. In particular, recursions over (von Neumann) ordinals can be made explicit. [Continued in next comment] | |
Jun 22, 2010 at 6:45 | history | edited | Philip Welch | CC BY-SA 2.5 |
Addition of alternate definition
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Jun 21, 2010 at 9:03 | history | answered | Philip Welch | CC BY-SA 2.5 |