Timeline for On the homotopy type of $\mathbb{QP}^\infty$
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Dec 27, 2017 at 7:47 | answer | added | Taras Banakh | timeline score: 3 | |
Dec 22, 2017 at 22:03 | answer | added | Prof. David Edwards | timeline score: 0 | |
Dec 22, 2017 at 21:52 | comment | added | fosco | This is a good answer too; what is known about the shape theory of this space? | |
Dec 22, 2017 at 21:48 | comment | added | André Henriques | Asking for the weak homotopy type of $\mathbb{QP}^\infty$ is the wrong question to ask, because that topological space does not have enough maps $\mathbb R^n\to \mathbb{QP}^\infty$. Instead, one should ask for its shape: en.wikipedia.org/wiki/Shape_theory_(mathematics) | |
Dec 22, 2017 at 21:22 | vote | accept | fosco | ||
Dec 22, 2017 at 21:12 | answer | added | Eric Wofsey | timeline score: 19 | |
Dec 22, 2017 at 21:10 | answer | added | Tim Campion | timeline score: 10 | |
Dec 22, 2017 at 20:44 | comment | added | fosco | (although there are a few things I would like to see in detail: why is this lifting possible -i.e. is the projection map a covering like in real and complex case?-) | |
Dec 22, 2017 at 20:43 | comment | added | fosco | @FanZheng maybe you saying that a path $\gamma : I \to \mathbb{QP}^\infty$ lifts along the projection from $\mathbb Q^\infty$? And the domain now is totally disconnected, I agree. | |
Dec 22, 2017 at 20:37 | comment | added | fosco | @FanZheng I'm not sure about anything, I'm just sitting here waiting for Eric to answer :-) | |
Dec 22, 2017 at 20:35 | comment | added | Fan Zheng | A path from $(a,\dots)$ to $(b,\dots)$ projects to a path from $a$ to $b$ in $\mathbb Q$, which is impossible if $a\neq b$. | |
Dec 22, 2017 at 20:33 | comment | added | Tim Campion | I would guess that it's totally path-disconnected, and so homotopically discrete. But that's just a guess. | |
Dec 22, 2017 at 20:22 | history | asked | fosco | CC BY-SA 3.0 |