Timeline for A double sequence in a Banach space
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Dec 24, 2017 at 11:10 | vote | accept | Matey Math | ||
Dec 24, 2017 at 0:50 | answer | added | Mikhail Ostrovskii | timeline score: 3 | |
Dec 21, 2017 at 16:30 | comment | added | Matey Math | @PietroMajer thanks for your answer and suggestion | |
Dec 21, 2017 at 16:29 | comment | added | Pietro Majer | To get the conclusion you wish, i would apply a dominated convergence for series, assuming the needed hypotheses. | |
Dec 21, 2017 at 16:17 | comment | added | Pietro Majer | I don't think it is true, if $\dim V>1$: given any $u$ and $u_0$ linearly independent, take $a_{n,m}:=\delta_{n,m}$, and $v_{n,n}:=u$ for all $n$ and $v_{m,n}:=u_0$ for $n\neq m$. | |
Dec 21, 2017 at 11:50 | comment | added | Matey Math | I thing it's true but i can't get the proof... and i need a proof | |
Dec 21, 2017 at 11:47 | comment | added | Michael Renardy | @GeraldEdgar: If V is 1-dimensional and $u_0\neq 0$, isn't it tautologically true that $u=au_0$ for some a? Don't you mean 2-dimensional rather than 1-dimensional? | |
Dec 21, 2017 at 11:31 | history | edited | Matey Math | CC BY-SA 3.0 |
added 21 characters in body
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Dec 21, 2017 at 11:31 | comment | added | Matey Math | @GeraldEdgar $V$ is infinite dimensiona, now i edit | |
Dec 21, 2017 at 11:20 | comment | added | Gerald Edgar | Is it true when $V$ is $1$-dimensional? If so, can that be used to prove your case? | |
Dec 21, 2017 at 10:24 | history | asked | Matey Math | CC BY-SA 3.0 |