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Dec 22, 2017 at 7:24 vote accept Alexander Braverman
Dec 19, 2017 at 16:16 answer added Tyler Lawson timeline score: 15
Dec 19, 2017 at 14:14 history edited Alexander Braverman CC BY-SA 3.0
added 80 characters in body
Dec 19, 2017 at 14:14 comment added Alexander Braverman I forgot to say that unit remain a unit
Dec 19, 2017 at 13:00 comment added Olivier Bégassat Given a ring define the bijection $\varphi:R\to R$ on the underlying set by imposing $\varphi(x)=-x$. Define a new ring structure $R^-$ on the underlying set $R$ by transfer of structure along $\varphi$. Addition is the same, but multiplication is given by $x\times^-x'=-xx'$. This should define a functor $C\to C$ where any morphism of commutative rings is sent to the same underlying set map. Since addition is the same, this functor commutes with the forgetful functor to abelian groups. Does this work ?
Dec 19, 2017 at 12:43 history asked Alexander Braverman CC BY-SA 3.0