Timeline for Bohr compactification as a topological compactification
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 18, 2023 at 8:00 | comment | added | Nick S | @UriBader Actually $G$ is open in $bG$ if and only if $G$ is compact (in which case $G=bG$). | |
| Dec 23, 2017 at 14:39 | vote | accept | XIII | ||
| Dec 21, 2017 at 20:09 | comment | added | Uri Bader | @HamedPourmohammad, $G$ is always dense in $bG$ by definition. The problem is that it might not be open in (or might not inject into) it. | |
| Dec 21, 2017 at 11:22 | answer | added | Uri Bader | timeline score: 5 | |
| Dec 21, 2017 at 0:13 | answer | added | Francois Ziegler | timeline score: 5 | |
| Dec 18, 2017 at 20:14 | comment | added | YCor | Would you define "topological compactification"? I'm not aware of any difference between "compactification" and "topological compactification". Does the latter mean that the subspace carries the compactification map induces a homeomorphism onto its image? | |
| Dec 18, 2017 at 19:24 | comment | added | XIII | Is it clear that Bohr compactification is not a topological comactification? Does it mean for example that $G$ is not dense in $bG$ (in the sense of topological compactifications)? @FrancoisZiegler | |
| Dec 18, 2017 at 19:20 | comment | added | XIII | Thanks. I don't know the topology of $b \mathbb{Z}$, good point. @GeraldEdgar | |
| Dec 18, 2017 at 19:09 | comment | added | Francois Ziegler | Bohr compactification (of a not already-compact group) is not a "topological" compactification. | |
| Dec 18, 2017 at 19:03 | comment | added | Gerald Edgar | Maybe first work on $b\mathbb Z$ and figure out whether the natural image of $\mathbb Z$ in there has the discrete topology. | |
| Dec 18, 2017 at 18:58 | history | edited | Wlodek Kuperberg | CC BY-SA 3.0 |
small corrections
|
| Dec 18, 2017 at 18:52 | review | First posts | |||
| Dec 18, 2017 at 19:01 | |||||
| Dec 18, 2017 at 18:47 | history | asked | XIII | CC BY-SA 3.0 |