Timeline for Can the Riemann integral be defined through a closure/completion process?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 14, 2017 at 21:37 | comment | added | Kusma | And no, it doesn't work, as this is just the same as the $L^1$ norm on step functions so the closure is all of $L^1$. The sets you get from Egorov's theorem aren't good enough to create step functions. | |
| Dec 14, 2017 at 16:06 | history | undeleted | Kusma | ||
| Dec 14, 2017 at 16:06 | history | deleted | Kusma | via Vote | |
| Dec 14, 2017 at 16:03 | comment | added | Kusma | sorry, I meant this to be a "comment", not an answer... | |
| Dec 14, 2017 at 16:00 | history | answered | Kusma | CC BY-SA 3.0 |