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Dec 10, 2017 at 23:57 comment added Joe Silverman In looking for patterns, it seems plausible that in the $n=4$ and $n=5$ formulas, the $\ln(2)$ term should be split into a multiple of $\ln(2)$ and a multiple of $\ln(4)$, and similarly in the $n=6$ formula some of the $\ln(2)$ and $\ln(3)$ terms should really be a $\ln(6)$ term. Possibly doing the computation by hand, rather than having Maple chunk out the answer, would give a plausible decomposition. Anyway, just a thought.
Dec 10, 2017 at 19:44 comment added Sylvain JULIEN The last constant term seems to be $ -\frac{(n+1)(n-2)+1}{n+1} $ .
Dec 10, 2017 at 14:29 history answered Shahrooz CC BY-SA 3.0