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Jan 16, 2018 at 21:42 vote accept CommunityBot
Jan 15, 2018 at 11:41 answer added Piotr Achinger timeline score: 3
Jan 15, 2018 at 10:50 comment added user85435 Thank you. It is really simple, but would you like to post this as an answer?
Dec 6, 2017 at 17:44 comment added Piotr Achinger $T_{A/S} = p^* p_* T_{A/S} = p^* {\rm Lie}_S A$, so the projection formula gives $R^1 p_* T_{A/S} = R^1 p_* p^* {\rm Lie}_S A = (R^1 p_* \mathcal{O}_A) \otimes {\rm Lie}_S A$.
Dec 6, 2017 at 15:24 history edited user85435 CC BY-SA 3.0
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Dec 6, 2017 at 15:18 history asked user85435 CC BY-SA 3.0