Timeline for How to prove the following polynomial does not have root of a special form?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Dec 6, 2017 at 23:47 | comment | added | Robert Israel | Indeed, if you take $x = 2 \cos(\alpha)$, $z = e^{i\alpha}$ is a root of $z^{16}+z^{14} - z^{10} - z^8 - z^6 + z^2 + 1$, which is $C_{30}(z^2)$ where $C_{30}$ is the 30'th cyclotomic polynomial. | |
| Dec 6, 2017 at 14:04 | comment | added | A. Mpi | If $n$ is even, i checked by computer and it doesn't have root of the given form. | |
| Dec 6, 2017 at 13:59 | comment | added | A. Mpi | Sorry, i forgot to say $n$ is even. | |
| Dec 6, 2017 at 13:23 | history | answered | assaferan | CC BY-SA 3.0 |