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Dec 6, 2017 at 1:19 comment added Pietro Majer Assuming $C$ invertible and writing $a:=Cu$ and $y:=u-x$, the equation writes $$Cy=(be^{\theta\cdot u})e^{-\theta\cdot y}$$ so the equation reduces to a scalar equation in $t\in\mathbb{R}$, after putting $y:=tC^{-1}b$, and can be solved in terms of the Lambert function.
Dec 6, 2017 at 1:17 review Close votes
Dec 6, 2017 at 11:15
Dec 6, 2017 at 1:03 history edited Tom Chen CC BY-SA 3.0
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Dec 6, 2017 at 1:01 comment added Will Jagy math.stackexchange.com/questions/2553126/…
Dec 6, 2017 at 0:52 review First posts
Dec 6, 2017 at 1:28
Dec 6, 2017 at 0:48 history asked Tom Chen CC BY-SA 3.0