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Timeline for 0-1 matrix combinatorial problem

Current License: CC BY-SA 3.0

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Dec 9, 2017 at 22:45 history edited Penelope Benenati CC BY-SA 3.0
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Dec 6, 2017 at 11:54 history edited Penelope Benenati CC BY-SA 3.0
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Dec 6, 2017 at 11:42 history edited Penelope Benenati CC BY-SA 3.0
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Dec 6, 2017 at 11:16 history edited Penelope Benenati CC BY-SA 3.0
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Dec 6, 2017 at 11:08 history edited Penelope Benenati CC BY-SA 3.0
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S Dec 5, 2017 at 12:22 history suggested Rodrigo de Azevedo CC BY-SA 3.0
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Dec 5, 2017 at 7:28 review Suggested edits
S Dec 5, 2017 at 12:22
Dec 4, 2017 at 22:59 comment added Greg Martin (I suggest editing those comments into the question)
Dec 4, 2017 at 20:30 comment added Penelope Benenati Do we have $R_{max}=\Theta\left((1/p-1)\,(n^{1/3}-1)\right)$ for any constant $c>0$ and $p \in (0,1/2]$?
Dec 4, 2017 at 20:29 history edited Penelope Benenati CC BY-SA 3.0
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Dec 4, 2017 at 20:07 comment added Penelope Benenati Think about having the first $n^{1/3}-1$ rows with all of their $1$s in the first $pn$ columns, the second $n^{1/3}-1$ rows with all their $1$s in the second $pn$ columns, and so on. This construction allows me to see that, for any constant $c>0$, we have $R_{max} \ge \left(\frac{1}{p}-1\right)\,(n^{1/3}-1)$. It is not clear to me whether there exists a matrix construction showing that $R_{max} = \omega\left(\left(\frac{1}{p}-1\right)\,(n^{1/3}-1)\right)$ for some constant $c>0$, when $n$ approaches infinity.
Dec 4, 2017 at 10:17 comment added Greg Martin What relative sizes of $p$ and $c$ are you interested in? What do simple constructions yield (like having the first $pn$ rows have all of their $1$s in the first $pn$ columns, the second $pn$ rows having all their $1$s in the second $pn$ columns, etc.), and do you think there are better constructions? I'm guessing you've done some work on this problem already, and it will enable actual helpful responses if you don't make readers reconstruct what you already know.
Dec 4, 2017 at 10:13 history edited Penelope Benenati CC BY-SA 3.0
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Dec 4, 2017 at 10:13 comment added Penelope Benenati Of course, sorry, I correct. Thanks.
Dec 4, 2017 at 10:11 comment added Greg Martin Presumably you mean $r_ir^T$?
Dec 4, 2017 at 10:04 history asked Penelope Benenati CC BY-SA 3.0