Timeline for Explicit forms for the roots of Eulerian polynomials
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
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| May 2 at 16:04 | comment | added | Hvjurthuk | In what sense is $|𝑞^{(𝑛)}_1|$ about $2^{𝑛}$? Could it be that, asymtotically, $|𝑞^{(𝑛)}_1|\sim\frac{2^{𝑛}}{n^{\beta}}$ or so? Because $𝑛^{1/𝑛}\to1$ when $𝑛\to\infty$. | |
| Dec 2, 2017 at 15:31 | history | answered | Richard Stanley | CC BY-SA 3.0 |