Timeline for Automorphisms of genus 6 surfaces
Current License: CC BY-SA 3.0
8 events
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| Jan 1, 2018 at 17:21 | comment | added | S.Lia | I have computed using MAGMA that there are no groups of order 240, 200 or 180 with generators with those orders. I would miss only a reference for the statement about the structure of the automorphism group, thank you. | |
| Nov 29, 2017 at 21:56 | history | edited | David E Speyer | CC BY-SA 3.0 |
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| Nov 29, 2017 at 21:44 | comment | added | Peter McNamara | re: footnote 1. By the classification of finite simple groups of order dividing 420, if G of order 420 has no abelian quotient, it must have A_5 as a quotient. Then since (7,60)=1, it must be a semi-direct product (Schur–Zassenhaus). Since A_5 can only act trivially on the cyclic group C_7, this must be a direct product. | |
| Nov 29, 2017 at 19:17 | history | edited | David E Speyer | CC BY-SA 3.0 |
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| Nov 29, 2017 at 17:57 | history | edited | David E Speyer | CC BY-SA 3.0 |
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| Nov 29, 2017 at 17:53 | comment | added | David E Speyer | Ah, which is indeed $S_3 \ltimes (\mathbb{Z}/5)^2$: permute the variables and multiply them by roots of unity. | |
| Nov 29, 2017 at 17:15 | comment | added | abx | 150 is the order of the automorphism group of the Fermat quintic $x^5+y^5+z^5=0$. | |
| Nov 29, 2017 at 17:01 | history | answered | David E Speyer | CC BY-SA 3.0 |