First I entirely agree with Yonatan that the main problem is with lemma 3.4. The specific problem that he mentions appears exactly because of the "degeneracies"degeneracy maps" that are added by Voevodsky and Kapranov to their category of diagrams. More precisely, one can, using the degeneracies, construct a diagrammatic setsset whose realization will "collapse" because of the Eckman-Hilton argument, and quite interestingly if one modifies their definition so that the category havehas no degeneracies then this no longer happenhappens (the free $\infty$-category is just obtained by "freely adding arrows" gradually as they assume it behavebehaves in the paper). So if one thinkthinks that degeneracies correspondscorrespond exactly to units, this is very encouraging for the Simpson conjecture. I haven't been able to make this into a clear counterexample of the lemma, but only because the lemma actually has other problems that appearsappear before that.
One should be able to formally "compose" the diagrams (and that it corresponds to pushout ofon the level of geometric realization) so that when you look at all the continuous functions $|D| \rightarrow X$ for all diagrams $D$ you indeed get an $\infty$-category.
That given two "parrallels""parallel" $n$-diagrams, you can construct an $n+1$$(n+1)$-diagramsdiagram whose source and target are the two given $n$-diagrams, so that if two diagrams shapediagram shapes are used to representsrepresent homotopically equivalent $n$-arrows then one can actually have aan $n+1$$(n+1)$-arrow that represents this homotopy.
It appears that both these properties failsfail for the kind of diagramdiagrams (Johnson'sJohnson diagrams) they are using ! Unfortunately, due to the fact that they actually use a slightly different construction than the one they explain in the introduction, these doesdo not immediately translate into mistakes in their paper.
This being said, they actually seemsseem to use that Johnson diagrams can be composed within the proof of the lemmaLemma 3.4 mentioned above, so that it is probably a second reason for which this lemma will fails.
It is not clear to me if (and where) they use the second property somewhere, but I expect some property of this kind should be important in order to prove that the geometric realization of diagramaticdiagrammatic sets indeed induces an equivalencesequivalence with the category of spacespaces (and they are extremely imprecise about how this equivalence is obtained, they just sayssay that "one does exactly as for simplicial and cubical sets" !).
For more details (and a third reason why lemmaLemma 3.4 failfails) I have a very recent preprint (https://arxiv.org/abs/1711.00744) which constructs a category of diagrams that havehas the two properties mentioned above as soon as you work in a 'non-unital' framework, unfortunately this category of diagrams is a lot more complicated than the category of Johnson diagramdiagrams (and it is unique so this complication is unavoidable) and this preventprevents from using the exact same strategy as they do. I discus in details in the appendix of the paper the proof of Kapranov and Voevodsky (this will expand a lot on this answer) and explain some ideas on how to make it into a proof of the Simpson conjecture using the category of diagramdiagrams that I constructed, but there are still some problemproblems that I do not know how to solve. This new version also havehas the advantage to make the two wayways of explaining the construction (in terms of generalized Moore homotopies and using two adjunctionadjunctions with a presheaf categoriescategory of diagramdiagrams in the middle) actually equivalent.