Timeline for Jacobian and configuration space and massey products
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 21, 2017 at 20:29 | comment | added | Cepu | Right! I tought the claim was about $\operatorname{Conf}_{l}(M)$. | |
| Nov 21, 2017 at 20:27 | vote | accept | Cepu | ||
| Nov 21, 2017 at 20:23 | comment | added | Dan Petersen | I don't understand what you mean. The map goes $H^2(M^l) \to H^2(\mathrm{Conf}_l(M))$, and the claim is that the Massey products vanish in $H^2(M^l)$. | |
| Nov 21, 2017 at 20:15 | comment | added | Cepu | Thanks! Could you explain why an isomorphism between first cohomology group implies an equality between Massey products? They are contained in the second cohomology group. Consider the map induced by $\operatorname{Conf}_{l}(M)\to M^{l}$ in the second cohomology group. I 'don't get why this map does not kill some Massey products. | |
| Nov 21, 2017 at 16:29 | comment | added | Dan Petersen | You're right, I was very confused. I edited the answer. | |
| Nov 21, 2017 at 16:29 | history | undeleted | Dan Petersen | ||
| Nov 21, 2017 at 16:29 | history | edited | Dan Petersen | CC BY-SA 3.0 |
added 210 characters in body
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| Nov 21, 2017 at 13:55 | history | deleted | Dan Petersen | via Vote | |
| Nov 21, 2017 at 13:51 | comment | added | Cepu | Thanks for your answer, It seems to me that you are saying that $V_{1}$ is generated by the ordinary product (all the higher product vanish), for any $l$. I'm right? Does this follows from the fact that $X\setminus{p}$ is formal, i.e. if $M$ is formal, then so is $\operatorname{Conf}_{l}(M)$? | |
| Nov 21, 2017 at 13:46 | comment | added | Cepu | I edit the question because of too many $n$ | |
| Nov 21, 2017 at 12:25 | history | answered | Dan Petersen | CC BY-SA 3.0 |